in reply to nested for loop with assumed scalars

You must name the loop variable for at least one of the loops.

for my $i ( 1 .. $#array1 ) {
    for my $j ( 1 .. $#array1 ) {
        print "$i $j\n";
    }
}

[download]

Makeshifts last the longest.

In Section Seekers of Perl Wisdom