Re^2: nested for loop with assumed scalars

I don't understand what do you mean by "problems with $#array". It would still be the index of the last item as defined:

$[ = 3;
@a = (1,2,3,4,5);
print $a[$#a];
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but of course I agree it's not a good idea to fiddle with $[.

Jenda
Always code as if the guy who ends up maintaining your code will be a violent psychopath who knows where you live.
-- Rick Osborne

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