matching string

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Hello monks , I am new to perl and have small question, I am trying to match some number inside a string : the sting is

$string1="version: 0410.1";
[download]

and I want to match only 0410.1 from that string , I tried:

$s_version =~ /version:\s([\w]+[\.\w+]*/;
[download]

but no luck ,, can someone advice ? thanks

Comment on matching string Select or Download Code

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Re: matching string by ikegami (Patriarch) on Aug 23, 2004 at 20:12 UTC
The only missing in your regexp is the closing `)`, and you're using different variable names (try `use strict;`). `$s_version = "version: 0410.1"; $s_version =~ /version:\s([\w]+[\.\w+]*)/; print("$1\n"); # 0410.1` [download] However, I recommend using insensate's easier to read expression.	[reply] [d/l] [select]
Re: matching string by insensate (Hermit) on Aug 23, 2004 at 20:02 UTC
`if($string1=~/version: (\d+\.\d+/){ $version=$1; print $version; }` [download] Should do the trick...	[reply] [d/l]
Re: matching string by ysth (Canon) on Aug 23, 2004 at 23:43 UTC
I think you are misunderstanding what [ ] do. They form a character class. ( ) or (?: ) are used for grouping. Your regex (with an ending ')' added) literally reads, find "version:" followed by one whitespace character followed by one or more word characters (digits, letters, or underscore), followed by zero or more characters that are either . or a word character. This is equivalent to the simpler regex `/version:\s(\w[.\w]*)/`, but I have the feeling you are looking for something else; perhaps `/version:\s(\d+\.\d+)/` or `/version:\s(\d+(\.\d+)?)/`.	[reply] [d/l] [select]