Yes folks, the person who wrote the original snippet created an array of 128 values, and assigned it to scalar.

Just a minor nitpick, it was the second poster who made the scalar/array context slip. (I'm the guy who posted the first code snippet;). True to my .sig, I didn't post my code until I knew I had the correct answer. In any case, the md5sum of the correct byte streams should be...

79054025255fb1a26e4bc422aef54eb4

As also noted on this page. Just for the heck of it, here's my original code. (and of course you should realize that it uses backticks to run a program called "echo" and "md5sum", hence the unix qualifier)

#!/usr/bin/perl -w
use strict;

my $v1=<<END_V1;
d1  31  dd  02  c5  e6  ee  c4  69  3d  9a  06  98  af  f9  5c
2f  ca  b5  87  12  46  7e  ab  40  04  58  3e  b8  fb  7f  89
55  ad  34  06  09  f4  b3  02  83  e4  88  83  25  71  41  5a
08  51  25  e8  f7  cd  c9  9f  d9  1d  bd  f2  80  37  3c  5b
d8  82  3e  31  56  34  8f  5b  ae  6d  ac  d4  36  c9  19  c6
dd  53  e2  b4  87  da  03  fd  02  39  63  06  d2  48  cd  a0
e9  9f  33  42  0f  57  7e  e8  ce  54  b6  70  80  a8  0d  1e
c6  98  21  bc  b6  a8  83  93  96  f9  65  2b  6f  f7  2a  70
END_V1

my $v2=<<END_V2;
d1  31  dd  02  c5  e6  ee  c4  69  3d  9a  06  98  af  f9  5c
2f  ca  b5  07  12  46  7e  ab  40  04  58  3e  b8  fb  7f  89
55  ad  34  06  09  f4  b3  02  83  e4  88  83  25  f1  41  5a
08  51  25  e8  f7  cd  c9  9f  d9  1d  bd  72  80  37  3c  5b
d8  82  3e  31  56  34  8f  5b  ae  6d  ac  d4  36  c9  19  c6
dd  53  e2  34  87  da  03  fd  02  39  63  06  d2  48  cd  a0
e9  9f  33  42  0f  57  7e  e8  ce  54  b6  70  80  28  0d  1e
c6  98  21  bc  b6  a8  83  93  96  f9  65  ab  6f  f7  2a  70
END_V2

my $p=join("",map {chr(hex($_))} split /\s+/, $v1);
my $q=join("",map {chr(hex($_))} split /\s+/, $v2);

print `echo -n \'$p\'|md5sum`;
print `echo -n \'$q\'|md5sum`;
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