Re^5: wantarray - surprise behaviour

in reply to Re^4: wantarray - surprise behaviour
in thread wantarray - surprise behaviour

No, the list *doesn't* come from the comma. It comes from the assignment:

sub foo {
    $c = wantarray;   
    print $c ? "A" : defined $c ? "S" : "V"
}

     (foo(), foo(), foo()); print "\n";   
$v = (foo(), foo(), foo()); print "\n";   
@v = (foo(), foo(), foo()); print "\n";   
__END__
VVV
VVS
AAA
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Re^6: wantarray - surprise behaviour by diotalevi (Canon) on Sep 01, 2004 at 17:43 UTC
Well, no. That's a case of a list in scalar or list context. I quote from perlop about the assignment operator. a list assignment in list context produces the list of lvalues assigned to, and a list assignment in scalar context returns the number of elements produced by the expression on the right hand side of the assignment.	[reply]

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