Re^3: how to force scalar context (without scalar())?

Ah, assignment… of course. You can inline it:

function(
  aa => ( my $aa = otherfunction() ),
  bb => ( my $bb = anotherone() ),
);
[download]

That's all the options available.

Makeshifts last the longest.

Comment on Re^3: how to force scalar context (without scalar())? Download Code

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Re^4: how to force scalar context (without scalar())? by borisz (Canon) on Sep 19, 2004 at 15:21 UTC
That exactly answer my question. Thanks. Boris	[reply]
Re^5: how to force scalar context (without scalar())? by ihb (Deacon) on Sep 19, 2004 at 21:40 UTC
I really really wonder how you can think that `func( aa => (my $aa = foo()), bb => (my $bb = bar()), );` [download] can be prettier than `func( aa => scalar foo(), bb => scalar bar(), );` [download] One can argue code aesthetics all day, but your assignment can be a real pain in the long run and all it does is to fool the maintenance programmer into thinking that you especially want those values later. If you do this, although please don't, at least use a `do` block to handle the scoping issue (and make the maintenance programmer scratch his head a little less). `func( aa => do { my $t = foo() }, bb => do { my $t = bar() }, );` [download] `ihb` Read argumentation in its context!	[reply] [d/l] [select]
Re^6: how to force scalar context (without scalar())? by borisz (Canon) on Sep 19, 2004 at 21:54 UTC
Thanks, but you missed the whole point of my question from the beginning. Please reread the question. My intent is _not_ to replace all occurrence of `scalar`. Nor I try to re-implement the `scalar` function. Boris	[reply] [d/l] [select]