in reply to Re^5: A "but" operator.
in thread A "but" operator.

Ahh! I see. I don't know why I was thinking you meant nand !(P and Q). I misunderstood your notation I guess.

The student's teacher would say ...

1 + 1 = 2 and 2 + 2 = 4 and 2 * 2 = 4 but 1 * 1 != 2

... which could be written as ...

1 + 1 = 2 and 2 + 2 = 4 and 2 * 2 = 4 and not (1 * 1 = 2)

I get it now.

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