in reply to whats wrong reverse %x = reverse %h?
Notice that when I try to use it to make an anonymous array:
I get a Bizarre copy of ARRAY in anonlist (perl v5.8.3). Same if I try to douse Data::Dumper; my %h = (1 => 2, a => "b", c => 2); print Dumper [ my %x = reverse %h ];
I have no idea what (my %x = reverse %h) evaluates to in list context, but whatever it is, Perl doesn't like it. The fact it doesn't die with the Bizarre copy error when using that expression as function arguments might be a bug...print Dumper { my %x = reverse %h };
Anyway, back to your original question, if you split the two reverses into two statements like
you'll get what you expect.%h = reverse do { my %q = reverse %h; %q };
blokhead
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