in reply to Re: It seems simple...
in thread It seems simple...

Unfortionatly, that doesn't work. 
s/\W|\s//g;

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successfully does what it says it will - both: 
s/\W//g;

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and 
s/\s//g;

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thereby eliminating the whitespace that I wanted to preserve (both regular expressions do that, actually)

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RE: RE: Re: It seems simple...
by plaid (Chaplain) on Feb 24, 2000 at 11:42 UTC
    Sorry, I misread your question the first time (me having posted the first answer).. I think what you want is $string =~ s/[^\w\s]//g;
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[d/l]
      Cool, that works. Thanks. The question now, though, is why? I know that: /^\w/ will match any word character at the start of a line and that /[]/ is character class stuff. Does the ^ actually negate or something similar instead of match the start of a line (in this context, of course)?
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[d/l]
[select]
      Now that I know what to look for, I finally found the explanation in man perlre . Ah, well. someday i'll read that in its entirerty.
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