Re: Finding / Replacing repetetive characters from a string in a Regular expression.

It looks to me like your expression is the equivilent of :

my @numbers = $aKnosId =~ m/([a-z]{2,})/g

Update I was totally wrong... sorry. Try this:

my @numbers = $aKnosId =~ m/(([a-z])(?:(?=\2)[a-z])+)/g

But then again Roy's answer is better.

May the Force be with you

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Re^2: Finding / Replacing repetetive characters from a string in a Regular expression. by Roy Johnson (Monsignor) on Oct 14, 2004 at 13:33 UTC
The difference is that your expression will match two (or more) different characters, while the OP wants to match two (or more) of the same. This should do it. `my @numbers = $aKnosId =~ /(([a-z])\2+)/g;` [download] Except that both captures get returned. So to fix: `my @numbers = grep {length > 1} $aKnosId =~ /(([a-z])\2+)/g;` [download] Caution: Contents may have been coded under pressure.	[reply] [d/l] [select]
Re^3: Finding / Replacing repetetive characters from a string in a Regular expression. by nims (Novice) on Oct 14, 2004 at 14:28 UTC
Thank you! Your solution works great :D.	[reply]