Re^2: How is this printing?

IIRC all $n variables get reset whenever a new regexp is uh... "done" (hope you understand me). Correct me if I'm wrong.

"2b"||!"2b";$$_="the question"
Besides that, my code is untested unless stated otherwise.
One more: please review the article about regular expressions (do's and don'ts) I'm working on.

Comment on Re^2: How is this printing? Download Code

Replies are listed 'Best First'.
Re^3: How is this printing? by Sandy (Curate) on Oct 19, 2004 at 17:04 UTC
Nope, I'm not exactly sure if I understand what you are asking, but here's my best guess... Consider the following code and result `foreach ("abc123", "xyz123","def12","ghi123") { /(.)123/; print "scanning $_: found $1\n"; } __DATA__ scanning abc123: found abc scanning xyz123: found xyz scanning def12: found xyz scanning ghi123: found ghi <code> Notice that while scanning "<code>def12` [download] " the "`$1`" variable was not reset* to `undef` but remains in its previously defined state. Was this what you were asking?	[reply] [d/l] [select]
Re^4: How is this printing? by muba (Priest) on Oct 19, 2004 at 20:18 UTC
It indeed is. Hmm, I think I can remember I read all $n got replaced, even if the regex did not match. Well, thank you. `"2b"\|\|!"2b";$$_="the question"` Besides that, my code is untested unless stated otherwise. One more: please review the article about regular expressions (do's and don'ts) I'm working on.	[reply] [d/l]