forcing array to scalar context in string interpolation?

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Perhaps this is a newbie question, but please be kind. I'm a newbie.

Given the following code:

my @array = qw/zero one two three/;
print @array, $/;
print "@array\n";
print "${@array}\n";
[download]

I get the following output:

14:38:57 ~/perl/source $ perl -w array
zeroonetwothree
zero one two three

14:38:59 ~/perl/source $
[download]

Without resorting to something akin to the following:

my @array = qw/zero one two three/;
my $n = scalar @array;
print "$n\n";
[download]

...which upon output yields:

14:44:42 ~/perl/source $ perl -w array
4
14:44:49 ~/perl/source $
[download]

How can I modify the interpolated string such that the element count of the list/array is substituted instead of the array contents?

Thanks.

Janitored by Arunbear - replaced pre tags with code tags, as per Monastery guidelines

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Re: forcing array to scalar context in string interpolation? by borisz (Canon) on Oct 20, 2004 at 21:57 UTC
`my @aa = qw/a b c d/; print scalar @aa, "\n"; print "@{[scalar(@aa)]}\n";` [download] Boris	[reply] [d/l]
Re: forcing array to scalar context in string interpolation? by BrowserUk (Patriarch) on Oct 20, 2004 at 22:01 UTC
`print @a . "\n"; print "${\(0+@a)}";` [download] Examine what is said, not who speaks. "Efficiency is intelligent laziness." -David Dunham "Think for yourself!" - Abigail "Memory, processor, disk in that order on the hardware side. Algorithm, algorithm, algorithm on the code side." - tachyon	[reply] [d/l]
Re: forcing array to scalar context in string interpolation? by kvale (Monsignor) on Oct 20, 2004 at 21:56 UTC
No need to put everthing inside double quotes. Try `print scalar @array, "\n";` [download] -Mark	[reply] [d/l]
Re: forcing array to scalar context in string interpolation? by qumsieh (Scribe) on Oct 20, 2004 at 23:16 UTC
`print 0+@array, "\n"; print "@{[scalar @array]}\n";` [download]	[reply] [d/l]
Re: forcing array to scalar context in string interpolation? by TedPride (Priest) on Oct 21, 2004 at 04:34 UTC
Heh, all he wants is the number of elements in the array: `my @array = qw/zero one two three/; print $#array;` [download] Where the number printed is the number of elements -1.	[reply] [d/l]