Re^5: Best way to make sure a number is an even multiple of another?

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Re^6: Best way to make sure a number is an even multiple of another? by thor (Priest) on Oct 21, 2004 at 14:32 UTC
In this case, there's an overload on the word "even". You're using it in the "divisible by two" sense, whereas in this context it means "an number m divides an integer n evenly if and only if there exists an integer k such that m * k = n". Stated another way, n % m == 0. thor `Feel the white light, the light within Be your own disciple, fan the sparks of will For all of us waiting, your kingdom will come`	[reply]
Re^6: Best way to make sure a number is an even multiple of another? by grinder (Bishop) on Oct 21, 2004 at 14:33 UTC
Looking at the table of data provided by demerphq, I suspect you should parse 'even' as 'exact'. - another intruder with the mooring of the heat of the Perl	[reply]
Re^6: Best way to make sure a number is an even multiple of another? by husker (Chaplain) on Oct 21, 2004 at 14:33 UTC
By "even multiple" I think he means "integer multiple". Looking at the table he provides, he does get "odd" results ($n = 7, $m = 3, fix ($n,$m) = 3).	[reply]