Re: Best way to make sure a number is an even multiple of another?

M goes into N int( N/M ) times, with a remainder of M%N.

So, M * (1 + int( N/M )) will be the smallest multiple of M greater then N.

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Comment on Re: Best way to make sure a number is an even multiple of another?

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Re^2: Best way to make sure a number is an even multiple of another? by Roy Johnson (Monsignor) on Oct 21, 2004 at 17:00 UTC
The trick is that what the OP wanted was greater than or equal to, without doing an if (or equivalent). Here's one way to modify your suggestion: `$m(($n%$m > 0) + int($n/$m));` [download] Caution:* Contents may have been coded under pressure.	[reply] [d/l]