in reply to Re: simple timeout
in thread simple timeout
For your alarm suggestion, I've tried trying to work with the alarm funtion but had no joy, for example the following doesn't work.
(using my $buf=<>; instead of the wmi stuff)
$SIG{'ALRM'}=\&time_out; while(1) { eval { alarm(5); my $buf=<>; alarm(0); }; print "next\n"; } exit; sub time_out { print "fed up waiting, next please\n"; die "FED UP WAITING"; }
The script should wait for user input, and get 'fed up' after 5 seconds. Problem being the alarm never seems to get called.
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Re^3: simple timeout
by disciple01 (Novice) on Nov 08, 2004 at 14:06 UTC | |
by zejames (Hermit) on Nov 08, 2004 at 14:30 UTC | |
by disciple01 (Novice) on Nov 08, 2004 at 16:49 UTC |