arrays passed into subroutines

amadain has asked for the wisdom of the Perl Monks concerning the following question:

Hi Monks
I want to pass 2 arrays into a subroutine but when I try I do not succeed. I use the following code to pass the arrays and check whether they are passed properly

sub team_update {
    my (@Values, @teams) = @_;
    print "Values are\n@Values and teams are\n@teams\n"; 
    exit 1;
}
[download]

but the check shows that the @Values array is the only one thats populated. Is there another way of doing this
Bewildered

Comment on arrays passed into subroutines Download Code

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Re: arrays passed into subroutines by wfsp (Abbot) on Nov 10, 2004 at 09:04 UTC
The arrays get flattened into one long list. `@_` pours it into the first place looking for a list i.e. `@Values`. You can pass the arrays as array references e.g. `\@array`. In the subroutine you then need to dereference them, say, `my $array_ref = shift; my @array = @{$array_ref};` [download] The perlreftut is a good place to delve deeper into refs.	[reply] [d/l] [select]
Re^2: arrays passed into subroutines by amadain (Novice) on Nov 10, 2004 at 09:15 UTC
Thanks. The array references worked fine	[reply]
Re: arrays passed into subroutines by neilh (Pilgrim) on Nov 10, 2004 at 08:56 UTC
When passing arrays you need to use references, otherwise the first is greedy... For more info see `perldoc perlref` Neil	[reply] [d/l]
Re^2: arrays passed into subroutines by Happy-the-monk (Canon) on Nov 10, 2004 at 09:33 UTC
passing arrays you need to use references Yes, but see also yesterday's meditation by grantm on how to use prototypes to hide the use of references and make `team_update ( @Values, @teams )` work as intended. Cheers, Sören	[reply]
Re: arrays passed into subroutines by Hena (Friar) on Nov 10, 2004 at 09:16 UTC
Also if you use prototypes, you can make your sub to be like `sub team_update (\@\@) { my ($values_ref,$teams_ref)=@_; }` [download] This would allow chaging the values within subroutine and also check that you call the subroutine properly (with strict).	[reply] [d/l]