HaB has asked for the wisdom of the Perl Monks concerning the following question:
------------------- e x c h a m p i o n b d f g j k l q r s t u v w y z . ! ? , The last 4 chars are just here to complete the table.
1 2 3 4 5 6 7 8 9 0 ------------------- a c e h i m n o p x j f b g q k s r l d y w t w ! z , ? . u
Now our table is complete. The way to use it is...you find the plaintext letter you want to encrypt, the ciphertext then becomes a two number set made of a randomly selected row number for that row, and the column number. So, plaintext 'a' becomes ciphertext 11, 41 or 71, 'b' becomes 23, 52, or 83, etc, etc.1 2 3 4 5 6 7 8 9 0 |--------------------- 1,4,7 | a c e h i m n o p x 2,5,8 | j f b g q k s r l d 3,6,9 | y w t w ! z , ? . u
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Script to find optimal words
by tedv (Pilgrim) on Nov 10, 2000 at 00:15 UTC | |
Re: Kiddie Codes
by Fastolfe (Vicar) on Nov 09, 2000 at 21:21 UTC | |
Try a list of list refs.
by TGI (Parson) on Nov 10, 2000 at 00:56 UTC | |
Re: Kiddie Codes
by HaB (Sexton) on Nov 09, 2000 at 21:19 UTC |