Because if $x is an object, then your regex won't work. (Nevermind that it won't work for reals or negative numbers.)
A stringification method (which your regex assumes) isn't reliable, because I could write a stringification method to output the number in hexidecimal, Base64, or as a roman numeral (see below) but as far as Perl was concerned, it could still operate just like a number):
package RomanNumber;
use Roman 'roman';
sub new {
my $class = shift;
my $self = { value => shift };
bless $self, $class;
}
sub as_num {
my $self = shift;
return $self->{value};
}
sub as_string {
my $self = shift;
return roman($self->as_num);
}
sub compare {
my ($a,$b) = @_;
return ($a->as_num <=> $b->as_num);
}
use overload
'0+' => \&as_num,
'""' => \&as_string,
'<=>' => \&compare;
If I add a few more numeric operators (it's an incomplete example), Perl can treat it just like a number, except that it outputs a roman numeral in string context.
There are cases where I would like to require a value to be number, but I would like to give the user of a module the ability to use a 'number-like' object rather than a number. |