Yes, use an integer for the counter, and derive the floating point number from it. Integers are represented accurately and they don't accumulate error (unless they grow beyond a certain size).

my $i=0;
print($i, "\n");
while ($i < 10){
    my $n = ++$i / 10;
    print($n, "\n");
}
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Update: oops, typo fixed.

for (0..10) {
  print $n/10,"\n";
}
[download]

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demerphq

just a small remark
your probably meant
    $n = $i / 10;
else you print out a few 0s
si_lence