in reply to regexp for scalar containing a mixture of LF & CRLF

What about something like:
s/\015?\012/\n/g;
Which will replace all LF and CRLF to whatever your local line ending character is.

Note: The /m modifier only affects the ^ and $ anchors, so is doing nothing in your RE since you have neither. The /s only affects what the . meta-character matches, and again, since you aren't using it, does nothing.

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Re^2: regexp for scalar containing a mixture of LF & CRLF
by NateTut (Deacon) on Dec 09, 2004 at 23:56 UTC
    Thanks but it didn't work. See my next post for the ugly way I finally got it to work.

    Doug