I'd like to know what the error means, but the real question is how to transform an array into a hash.
...
%data = @info =~ /(\w+)\s*(\w+)/g;    # Line that gives error
...
Applying pattern match to @array will act on scalar(@array) at e.pl line 29

You can get more information on any error by putting "use diagnostics;" in your script (or looking up the error via perldoc perldiag or the splain utility).

$ echo 'Applying pattern match to @array will act on scalar(@array) at
+ e.pl lin
e 29'|splain|fmt
Applying pattern match to @array will act on scalar(@array) at e.pl li
+ne
29 (#1)
    (W misc) The pattern match (//), substitution (s///),
    and transliteration (tr///) operators work on scalar values.
    If you apply one of them to an array or a hash, it will convert th
+e
    array or hash to a scalar value -- the length of an array, or the
    population info of a hash -- and then work on that scalar value.
    This is probably not what you meant to do.  See perlfunc/grep and
    perlfunc/map for alternatives.
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