in reply to Safe to use ternary operator like this?

I have to run, but I just saw this...
this is how I would do it: 
my $Temp=&Func() || 'undefined';

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Bye!!

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Re: Re: Safe to use ternary operator like this?
by arturo (Vicar) on Nov 16, 2000 at 20:48 UTC

    This will set $Temp to 'undefined' if &Func returns a false value (see What is true and false in Perl? for more details). I like the original code, methinks. It's just what the ternary operator was designed to do.

    Philosophy can be made out of anything. Or less -- Jerry A. Fodor

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Re: Re: Safe to use ternary operator like this?
by Albannach (Monsignor) on Nov 16, 2000 at 20:43 UTC
    Not quite the same thing depending on the sub return though: 
    use strict;
my $temp;

$temp = defined ($temp = func()) ? $temp : 'undefined';
print "func:$temp\n";

$temp = func() || 'undefined';
print "func:$temp\n";

sub func { return ''; }

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    produces: 
    func:
func:undefined

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