in reply to Making regex /g match continuously

It sounds like what you want is to start with \G, instead of ^. \G matches the location where the last /g match ended. (See pos and search perlop and perlre for \G for more details and examples.)

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Re^2: Making regex /g match continuously
by scottb (Scribe) on Jan 07, 2005 at 20:06 UTC
    Eimi,

    That is good info and really helps, the only remaining problem is that the following regex still succeeds in matching 'A' in the example data I provided.

    \G ^(?:int)\s+(\w+)\s*?\n (?:\s*Number\sof\sFlaps:\s(\d+)\s*?\n)? (?:\s*IP\sAddress:?\s([\d\.]+)\s*?\n)? (?=^int|\Z)
    Is there any way to pull it off where the whole regex fails that I am missing?
      You have a couple of options:
      1. You can do a match on the whole expression, and do the iterative (/g) match if the whole expression matches,
      2. You can accumulate the captures from the iterative match (on edit: using the /c option), and then test against /\G\Z/g before processing your way through them,
      3. You can lookahead the whole rest of the expression (I don't recommend this, because it duplicates a lot of effort compared to method 1).
      # Option 1: my $item_regex = qr/ (?:int)\s+(\w+)\s*?\n (?:\s*Number\ of\ Flaps:\s(\d+)\s*?\n)? (?:\s*IP\sAddress:?\s([\d\.]+)\s*?\n)? /x; while (<DATA>) { if (/^$item_regex+\Z/) { print "$1, $2, $3\n" while (/\G$item_regex/g); } }

      Caution: Contents may have been coded under pressure.
        Thanks. I think I like the second approach best.

        If I can, a bit of an elaboration though; of the 3 approaches you suggested, which is most efficient when there is not a match? I notice that when my complicated regex's do not match that I max the CPU on my server and the HTTP aspect has to time out. If the regex matches, it takes mere fractions of a second.

        Is there a way within these approaches that I can minimize the wasted effort of the regex in a case that not all 'int's will match?

        Thanks again.