in reply to Merge Hashrefs

$object = { %$object, %$subobject };

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Re^2: Merge Hashrefs
by MiroslavK (Initiate) on Oct 15, 2014 at 15:32 UTC
    But this goes only one level deep. For "deeper" hash structures (like $object->{level1}{level2}=$value) this fails. See example:
    use strict; use Data::Dumper; my $x = { a => 1, b => 2, aa => { aaa => 11 } }; print Dumper($x); my $y = { c => 3, d => 4, aa => { bbb => 11 } }; print Dumper($y); $x = { %$x, %$y }; print Dumper($x);
    Gives (see below) with "aaa" key in 'aa'=>'aaa'=>22 lost
    $VAR1 = { 'c' => 3, 'a' => 1, 'b' => 2, 'd' => 4, 'aa' => { 'bbb' => 11 } };
    UPDATE: check this thread how to do it using Hash-Merge http://www.perlmonks.org/?node_id=1015801 In a nut shell, add as appropriate:
    use Hash-Dumper qw/merge/;
    and modify
    $x = { %$x, %$y };
    to
    $x = merge( $x, $y );
    and resulting hash will look much better
    $VAR1 = { 'c' => 3, 'a' => 1, 'b' => 2, 'd' => 4, 'aa' => { 'bbb' => 11, 'aaa' => 11 } };
      > But this goes only one level deep.

      Of course!

      Since there are many possible interpretations of what a "deep merge" should do, you should script it in a recursive way after your well defined needs.¹

      Cheers Rolf

      (addicted to the Perl Programming Language and ☆☆☆☆ :)

      update

      see also how to merge hash deeply ?

      ¹) for example what do you expect to happen if both hashes have the same scalar entry?

      %a = (x=>1}; %b = (x=>2);
Re^2: Merge Hashrefs
by oakbox (Chaplain) on Jan 10, 2005 at 12:44 UTC
    Well I guess that is simple enough!

    Thank you

      Note that the above is *really* inefficient (or at least it was). You might consider:  @hash1{ keys %hash2 } = values %hash2; Which is more efficient.