Quick Regex question

damian1301 has asked for the wisdom of the Perl Monks concerning the following question:

Replies are listed 'Best First'.
Re: Quick Regex question by swiftone (Curate) on Nov 18, 2000 at 02:34 UTC
Bind the string to the operation using =~ (see perlop): `$blah2 =~ s/\w+//;` [download] Update: Note this doesn't prevent you from doing this: `my ($word) = $string =~ /(\W+)/;` [download] But you should be careful about maintainability. This trick appears to only work with the m// construct in list context.	[reply] [d/l] [select]
Re: Re: Quick Regex question by runrig (Abbot) on Nov 18, 2000 at 02:45 UTC
Mistake. sorry. This node scheduled for removal (hopefully!).	[reply]
Re: Quick Regex question by Nimster (Sexton) on Nov 18, 2000 at 02:35 UTC
try the =~ operation syntax string buzzword (was in original post: thingy) `$blah=~s/\W+/$blah2/` just had to be the first to comment, but I missed it anyway. Didn't want to be left behind when swiftone started editing his! This doesn't prevent you from doing `my ($something) = my ($something2) = $blah =~s/\W+/$blah2/` [download] Beat that, swiftone! :) -Nimster	[reply] [d/l] [select]
Re: Quick Regex question by damian1301 (Curate) on Nov 18, 2000 at 02:56 UTC
`$one = "<HTML><Just testing this thing>"; $one =~ s/\W+/ /;` [download] for all u people that wanted to see my test project thingamajig, here it is.	[reply] [d/l]
Re: Re: Quick Regex question by swiftone (Curate) on Nov 18, 2000 at 02:59 UTC
I'll post a nice verbose post to elucidate this for everyone not involved in the chatterbox: You wanted to replace all non-word characters with spaces. The pattern you listed wasn't working. The problem was that you didn't use the /g modifier, so it only replaced the first matching expression.	[reply]
Re: Re: Re: Quick Regex question by chromatic (Archbishop) on Nov 18, 2000 at 08:36 UTC
In that case, I wouldn't use s/// at all. tr/// is faster and fits better, conceptually. `tr/a-zA-Z0-9/ /c;` I really like that /compliment switch.	[reply] [d/l]