in reply to CloneArmyCommander Tries His Luck at JAPH

++ CloneArmyCommander :-) That had me there for a bit, cause I didn't understand what you were doing replacing each '.' with a word boundary (\b). Then I realised it was actually a backspace.I'm assuming this means (correct me if I'm wrong) in the 'match part' of the s/// operator, a '\b' matches a word boundary; but in the 'replace part' it replaces with a backspace. At least this was the case when I tested with perl -ple "s/\b/./g" Am I going in the right direction, anyone?

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Re^2: CloneArmyCommander Tries His Luck at JAPH
by CloneArmyCommander (Friar) on Jan 27, 2005 at 19:30 UTC
    I was asking myself how I could possibly add more useless code to make it look bigger, so I took the letters in "Just Another Perl Hacker," I just made into "JKuvsttu. . ." using the letter that comes after, seperated every two letters with "." and I replaced the dot with a backspace which also gets rid of the extra character after each letter :). I like to play around with the escape sequences to see what kinds of results I can get from them :). I just happened to be playing with the backspace that day :).

    Thanks for the complement :). I would have replied earlier, but I have not had much internet time to come in and actually write since college started back.
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