Re^2: Assign multiple scalars the same value

Jeepers! the 'x' operator works on lists too!?

Looks like time to refactor out all ...

my ($a,$b,$c) = map {'TRUE'}(0 .. 2);
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Re^3: Assign multiple scalars the same value by Aristotle (Chancellor) on Jan 24, 2005 at 22:52 UTC
Yep, it does. Note the difference between these, though: `$,= " "; $\ = "\n"; print( map { int rand 10 } 0 .. 6 ); print( ( int rand 10 ) x 7 );` [download] The `x` operator only evaluates the list expression once. So you can't always substitute one for the other. Makeshifts last the longest.	[reply] [d/l]
Re^3: Assign multiple scalars the same value by Limbic~Region (Chancellor) on Jan 25, 2005 at 14:31 UTC
scooterm, Not only that, but if the what the list contains is a reference, the reference is replicated as well. The first useful application I remember seeing of this is in tye's Algorithm::Loops. I found a useful variation that looked a little something like: `my @signal = qw(ABRT STOP TERM INT); @SIG{ @signal } = (sub { kill 9, $pid; exit }) x @signal;` [download] Incidently, diotalevi makes a good point concerning ensuring that you have the same number of things on both sides of the assignment which is not an issue in my example. Cheers - L~R	[reply] [d/l]