Re: "Secret" operators

You may be familer with the spaceship operator already (<=>). What about the Super Star Destroyer operator?

${-} <=$vader=> ${-}
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Update: Now complete with TIE Intercepters!

"There is no shame in being self-taught, only in not trying to learn in the first place." -- Atrus, Myst: The Book of D'ni.

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Re^2: "Secret" operators by cog (Parson) on Jan 28, 2005 at 18:00 UTC
Ok, I tried it out and now I have some doubts... `$a <=$b=> $c` is equal to `( $a <= $b , $c)`, that one is easy... But what happens if I just use `<=$something=>`? Because printing that prints an equal sign, the contents of $something and another equal sign... I'm missing something, here...	[reply] [d/l] [select]
Re^3: "Secret" operators by mauke (Novice) on Jan 29, 2005 at 15:54 UTC
That's the `<>` operator. `=$something=` isn't a simple scalar, so it's equivalent to `glob("=$something=")`. On the other hand, `<$something>` means `readline($something)`. (For special weirdness, `<$ something>` is the same as `glob($something)`.) See glob, readline and I/O Operators in perlop for details.	[reply] [d/l] [select]
Re^3: "Secret" operators by hardburn (Abbot) on Jan 28, 2005 at 18:25 UTC
I tried `<=$vader=>` (and also `<==>`), but they are both syntax errors. That's why I added the TIEs :) "There is no shame in being self-taught, only in not trying to learn in the first place." -- Atrus, Myst: The Book of D'ni.	[reply] [d/l] [select]