in reply to Re: string substitution within regular expressions?
in thread string substitution within regular expressions?

Okay, utilizing the code suggested above, I get the expected behaviour. If I change the if-statement to the following, I get the errors noted further below.
#!/usr/bin/perl my $s = 'Tue Feb 8 11:11:11 2005: blah blah blah'; my $regex = '^$wday $mon\s+$mday \d{2}:\d{2}:\d{2} $year:'; my $wday = 'Tue'; my $mon = 'Feb'; my $mday = '8'; my $year = '2005'; findString($s); sub findString($) { my $line = shift; # print "found\n" if $line =~ eval "qr/$regex/"; if ($line =~ eval "qr/$regex/") { print "found\n"; } }
Do the following errors make sense? Yes, I'm using Perl 5.005, but I cannot change this at this point.
Scalar found where operator expected at (eval 1) line 1, at end of lin +e (Missing operator before ?) Backslash found where operator expected at (eval 1) line 1, near "$mon +\" (Missing operator before \?) found
Placing curly braces around the qr() string pacifies the interpreter, but I no longer see the expected answer. Thanks for any insight.

Replies are listed 'Best First'.
Re^3: string substitution within regular expressions?
by Roy Johnson (Monsignor) on Feb 09, 2005 at 12:16 UTC
    The errors don't make any sense to me, given that it works in the non-block if and only fails with block-form if. Does this work any better? Does it fail before the if?
    sub findString($) { my $line = shift; my $compiled_regex = eval "qr/$regex/"; if ($line =~ /$compiled_regex/) { print "found\n"; } }

    Caution: Contents may have been coded under pressure.
      Works like a champ. Thanks!