... the rest are off by a few bits.
The only way that can be true, is if
- the sync mark itself is not meant to be on a byte boundary.
Ie. If it is meant be a few bits into each frame?
This is possible and easily dealt with.
- Or the frames are themselves are "a few bits" longer than 960 bytes, which doesn't makes much sense.
Could you unpack the first 3 or 4 frames of the (raw) file to binascii and post them on your scratchpad?
Examine what is said, not who speaks.
Silence betokens consent.
Love the truth but pardon error.
| [reply] |
Sorry, the company would frown upon that. I think my problem is that I'm reading in the equivalent of 2 frames but have to discard so many bits to get to the sync. afterwhich I no longer have a frame left that's on a byte boundary. This is why I am currently writting the ascii-ized binary out to a file then reopening and going though the file to pack it back. I forgot I had changed that part of the code.
| [reply] |
Read
|------------|------------|------------|------------|---|
---------------------------------------------------------
....|s 7680 bits |s 7680 bits |s 7680 bits |s 7680 bits |
---------------------------------------------------------
write
<<<<|s-------|----s-------|----s-------|----s-------|---|
|s-------|----s-------|----s-------|----s-------|---|
-----------------------------------------------------
|s 7680 bits |s 7680 bits |s 7680 bits |s 7680 bits |
-----------------------------------------------------
Anyway, good luck.
Examine what is said, not who speaks.
Silence betokens consent.
Love the truth but pardon error.
| [reply] [d/l] |