For your example, that would be 2 * sqrt(2*5) * 5, which turns out to be exactly the correct answer, 31.622..

Cheers,

Needless to say, but I'll say it anyway, a fascinating problem. Exactly the kind of thing that my Dad eats for breakfast (retired actuary and all that).

After some thought, it seems clear that this is a tough nut to crack. If you start with a sorted list of factors, largest to smallest, and multiply values together, the solution is 25. If you drop the first value, you end up with 20. I can't prove it (not at 0630, anyway), but I expect there are cases where the solution is the product of the first, second and last factors.

In the end, I think the best way to find out the answer is to figure out the integer that's closest to the square root, then go backwards to find the largest number made up of the factors. Assuming you don't want to actually calculate the suqare root, the first part of that can be a straightforward binary search. The second part is where it gets interesting .. you have to find the combination of factors whose product is closest to the approximate square root value you've determined.

And that sounds an awful lot like re-starting the original problem. Ugh.

Alex / talexb / Toronto

"Groklaw is the open-source mentality applied to legal research" ~ Linus Torvalds

This discussion and my own (preliminary) benchmarking results have led me to rethink a few things about my real problem.

For instance, when computing F(n), we can make use of the addition formula to break n into 2 pieces:

F(n) = F(i+j) = F(i-1)*F(j) + F(i)*F(j+1)
[download]

Then:

j = k**2 = int(sqrt(n))
i = n - j
F(n) = F(i+j) = F(i+k**2)
[download]

which we can compute using the first formula above and

F(k**2) = (F(k-1)+F(k+1))*F(k*(k-1)) 
          - ((-1)**k)*F(k*(k-2))
[download]

It remains to be seen whether all of this extra work buys anything.

-QM
--
Quantum Mechanics: The dreams stuff is made of