Re: qx and stderr

are you using strict?
is the definition of command declared in single or double quotes?

$output = `ls -? 2>&1` works fine for me

Update: Hmm.. I thought that defining in double quotes using &1 would possible cause problems - hence the strict question - no matter. But:

my $cmd = "ls -? 2>&1";
$output = qx/$cmd/;

print "-" x 50, "\n", $output, "\n", "-" x 50, "\n"
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works fine for me

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It's sad that a family can be torn apart by such a such a simple thing as a pack of wild dogs

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Re^2: qx and stderr by Anonymous Monk on Feb 23, 2005 at 18:53 UTC
no, i'm not using strict. but your inquiry about quoting may be my problem. this is how i'm putting a value into $cmd: qq/remsh $ctm_server -l ctmsrv "ctmshout -dest ECS -message '$msg'"/ i've got quotes on top of quotes on top of quotes (sigh). perhaps 2>&1 should be inbetween the last single and double (literal) quotes? - d	[reply]
Re^3: qx and stderr by RazorbladeBidet (Friar) on Feb 23, 2005 at 19:00 UTC
Ohh... well, not sure what NIX you're using, but the -a flag for remsh might help (as will the -n flag). Have you tried those? -------------- It's sad that a family can be torn apart by such a such a simple thing as a pack of wild dogs*	[reply]