Re: regexp find last word

s/(fox.+)(fox.+?forest)/${1}the $2/;
[download]

Your regex matches at the earliest possible position. That weighs more than the laziness caused by the ?. Therefore you need to force it behind the first "fox".

holli, /regexed monk/

Comment on Re: regexp find last word Download Code

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Re^2: regexp find last word by Roy Johnson (Monsignor) on Mar 02, 2005 at 15:16 UTC
You should ?-quantify the first parenthesized expression, so it works for one fox as well: `s/(fox.+)?(fox.+?forest)/${1}the $2/` [download] Caution: Contents may have been coded under pressure.	[reply] [d/l]
Re^2: regexp find last word by manav (Scribe) on Mar 02, 2005 at 15:39 UTC
What happens in case of fox comes and the fox goes into forest The code given above will put a the in front of every last fox irrespective of if a the was already there or not. `while(<DATA>) { s/(?<!the )fox(?!.*fox)/the fox/ ; print; } __DATA__ the fox comes and fox goes into forest fox comes and fox goes into forest the fox comes and the fox goes into forest fox comes and the fox goes into forest` [download] Manav	[reply] [d/l]
Re^2: regexp find last word by Anonymous Monk on Mar 02, 2005 at 14:55 UTC
That works, but it will not work if you have two foxes and two forests and you want to slap a `/g` on it.	[reply]