Re^3: Find if a number is a multiple of a number.

The docs: from perlop

Binary "%" computes the modulus of two numbers.Given integer operands
$a and $b: If $b is positive, then "$a % $b" is $a minus the largest
multiple of $b that is not greater than $a.  If $b is negative then
"$a % $b" is $a minus the smallest multiple of $b that is not less tha
+n
$a (i.e. the result will be less than or equal to zero).  Note that
when "use integer" is in scope "%" gives you direct access to the mod-
ulus operator as implemented by your C compiler.  This operator is not
as well defined for negative operands, but it will execute faster.
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Boris

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Re^4: Find if a number is a multiple of a number. by blazar (Canon) on Mar 03, 2005 at 13:59 UTC
Binary "%" computes the modulus of two numbers.Given integer operands $a and $b: If $b is positive, then "$a % $b" is $a minus the largest multiple of $b that is not greater than $a. If $b is negative then "$a % $b" is $a minus the smallest multiple of $b that is not less than And... so what? $a (i.e. the result will be less than or equal to zero). Note that when "use integer" is in scope "%" gives you direct access to the mod- ulus operator as implemented by your C compiler. This operator is not as well defined for negative operands, but it will execute faster. Is this the particular point on which you meant to draw the attention? If so, then it actually is a good point, however IMHO it belongs more to the realm of side notes...	[reply]

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Re^4: Find if a number is a multiple of a number.
by blazar (Canon) on Mar 03, 2005 at 13:59 UTC

Binary "%" computes the modulus of two numbers.Given integer operands $a and $b: If $b is positive, then "$a % $b" is $a minus the largest multiple of $b that is not greater than $a. If $b is negative then "$a % $b" is $a minus the smallest multiple of $b that is not less than

$a (i.e. the result will be less than or equal to zero). Note that when "use integer" is in scope "%" gives you direct access to the mod- ulus operator as implemented by your C compiler. This operator is not as well defined for negative operands, but it will execute faster.

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