in reply to Re: the '..' operator and decreasing values
in thread the '..' operator and decreasing values
this doesn't work as I expectedThe key element there being "I".
Perl works as Larry expects. It's up to the rest of us to figure out what that means. (And for some of us to write about it and teach it.)
-- Randal L. Schwartz, Perl hacker
Be sure to read my standard disclaimer if this is a reply.
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