Re^5: Smart match in p5

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Re^6: Smart match in p5 by xmath (Hermit) on Mar 14, 2005 at 18:09 UTC
If you had bothered to read the original meditation, you'd have seen the remark: Note that prefix '~~' still works like it did previously. Therefore if foo is a sub, then foo~~bar will be parsed as foo(~~bar) unless foo has prototype (). To get a smartmatch on the result of foo, you'd write `foo() ~~ $var`	[reply] [d/l]