given time1a and b how much is in time2a and b

blueberryCoffee has asked for the wisdom of the Perl Monks concerning the following question:

Hello all wise monks, I am making a time tracking program. Currently I record the start time and end time (with perl's time function) of a project as I work on it each day. Are there any functions anyone knows of that I can use to show how much time was spent within a range?

I guess I am envisioning something like
$secs += secondsInRange($projectStart, $projectEnd, "1/12/2005", "1/18/2005")
Or
$secs += secondsInRange($time1a, $time1b, $time2a, $time2b)

Thanks in advance,

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Re: given time1a and b how much is in time2a and b by tlm (Prior) on Mar 30, 2005 at 22:35 UTC
Sounds like interval arithmetic: `use List::Util qw( min max ); sub overlap { my @intervals = @_[0, 1]; my $left = max( map $_->[ 0 ], @intervals ); my $right = min( map $_->[ 1 ], @intervals ); return max( 0, $right - $left ); }` [download] Just turn the 3rd and 4th args to seconds relative to the epoch, and use the above function, with the intervals passed as array refs `[ $time1a, $time1b ]`, `[ $time2a, $time2b ]`. the lowliest monk	[reply] [d/l] [select]
Re: given time1a and b how much is in time2a and b by fglock (Vicar) on Mar 31, 2005 at 03:47 UTC
DateTime::SpanSet can do this for you: use DateTime::SpanSet; my $dt1 = DateTime->new( year => 2005, month => 1, day => 1 ); my $dt2 = DateTime->new( year => 2005, month => 1, day => 4 ); my $dt3 = DateTime->new( year => 2005, month => 1, day => 7 ); my $dt4 = DateTime->new( year => 2005, month => 1, day => 9 ); my $dt_spanset = DateTime::SpanSet->from_spans( spans => [ DateTime::Span->from_datetimes( start => $dt1, end => $dt2 ), DateTime::Span->from_datetimes( start => $dt3, end => $dt4 ), ] ); print "duration: @{[ $dt_spanset->duration->deltas ]}\n"; # duration: months 0 days 5 minutes 0 seconds 0 nanoseconds 0 [download]	[reply] [d/l]