in reply to Re^2: Skipping the middle man & the SUPER gotcha
in thread Skipping the middle man & the SUPER gotcha

O Guru,

If the method name is fully-qualified, how could @ISA be used to any effect? When using a fully-qualified method name, doesn't that routine get called regardless of what's in @ISA? (The "other" package isn't in @Me::ISA, in my example above, and yet &other::hello() gets called, and with $me as an argument.)

-- A Humble Grasshopper

  • Comment on Re^3: Skipping the middle man & the SUPER gotcha

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Re^4: Skipping the middle man & the SUPER gotcha
by TimToady (Parson) on Apr 02, 2005 at 20:00 UTC
    No, with the arrow notation, the extra class information just tells it where to start looking in the class hierarchy. It's only identical to a sub call if the method in question is actually found in the class you named.
[reply]
      Thanks for that. It's clear now, and suprising!

      It doesn't even matter what package the invocant is blessed into, or even if it's an arbitrary bare word. 

      use strict;
use warnings FATAL => 'all';

package Base;
sub hello { print __PACKAGE__.": @{[ref $_[0] || $_[0]]}\n"; }

package Kid;
our @ISA = 'Base';

package Main;
sub hello { print __PACKAGE__.": @{[ref $_[0] || $_[0]]}\n"; }

package main;
our @ISA = 'Main';

my $main = bless {};
$main->Kid::hello;    # Base: main
$main->hello;         # Main: main

__PACKAGE__->hello;   # Main: main
BareWord->Kid::hello; # Base: BareWord

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