Re: How can I place each "word" of a string in a varible if I don't know the length of the string?

You ought to use split if you don't know the number of "words" (and by words I'm assuming you mean space-delimited text) ahead of time. Heck, even if you do you should use split. For example:

# Yes, I know how many "words" there are.
($word_one, $word_two, $word_three) = split " ", $sentence;

# No, I don't know how many words there are.
@words = split " ", $sentence;
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The second example gives you an array filled with all the words in the sentence, in order. Now, if your question is how to put all the words into individually named scalar variables the answer is you can't. I mean, logically, how can you put n number of words into n number of scalars when n is unknown? You can't. That's why God invented the array, so you don't have to know. @words will be exactly as long as the number of words in your sentence, and you can get to each one whenver you wish, and have your nasty little way with them.

Gary Blackburn
Trained Killer

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Re: Re: How can I place each "word" of a string in a varible if I don't know the length of the string? by Beelzebub (Initiate) on Dec 05, 2000 at 19:16 UTC
Why don't you just split the @words array again, this time in a loop, stating that each variable in the array becomes its own ($word1 , $word2 , etc.) scalar ? The 1, 2, 3, you can create with a simple increment. Does that contribute to the solution ?	[reply]