Re^20: Why is the execution order of subexpressions undefined?

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The Glorious Glasgow Haskell Compilation System, version 6.2.2
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Re^21: Why is the execution order of subexpressions undefined? by Anonymous Monk on Apr 15, 2005 at 14:39 UTC
So then you're going to show us a piece of code which is slower in Haskell than in Perl?	[reply]
Re^22: Why is the execution order of subexpressions undefined? by BrowserUk (Patriarch) on Apr 15, 2005 at 14:44 UTC
Efficiency is not only about speed. Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error. Lingua non convalesco, consenesco et abolesco. Rule 1 has a caveat! -- Who broke the cabal?	[reply] [d/l]
Re^23: Why is the execution order of subexpressions undefined? by Anonymous Monk on Apr 15, 2005 at 14:47 UTC
So then you're going to show us a piece of code which is ~~slower~~ less efficient in Haskell than in Perl?	[reply]
Re^24: Why is the execution order of subexpressions undefined? by BrowserUk (Patriarch) on Apr 15, 2005 at 19:05 UTC
GHC shuffle more efficient than Perl5. by audreyt (Hermit) on Apr 22, 2005 at 14:23 UTC
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Haskell and inplace sorting by audreyt (Hermit) on Apr 22, 2005 at 09:12 UTC
Re^25: Why is the execution order of subexpressions undefined? by Anonymous Monk on Apr 18, 2005 at 01:23 UTC
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