in reply to Re^2: Implicit split to @_
in thread Implicit split to @_
Er are you sure:
vsperl -e 'my $sa = () = split //,"foo"; print $sa'
split() is outwitting us here - it sees the empty list and optimizes accordingly.perl -e 'my $sa = do {my @tmp = split //,"foo"}; print $sa'
/J\
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Re^4: Implicit split to @_
by Anonymous Monk on Apr 15, 2005 at 15:12 UTC |