Re^26: Why is the execution order of subexpressions undefined?

You were so close. Did you think about what

my $two_lines = ( read_a_line() ) . read_a line();
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would mean if EO was defined?

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

Lingua non convalesco, consenesco et abolesco.

Rule 1 has a caveat! -- Who broke the cabal?

Comment on Re^26: Why is the execution order of subexpressions undefined? Download Code

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Re^27: Why is the execution order of subexpressions undefined? by Anonymous Monk on Apr 15, 2005 at 14:51 UTC
Why would it be any different than without the set of parenthesis?	[reply]