Re: Copy of an anonymous hash?

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Re^2: Copy of an anonymous hash? by DrHyde (Prior) on Apr 26, 2005 at 09:37 UTC
That works, but only if the hash contains simple scalars. If it contains any references, the reference will be copied, so you'll have two references to the same thingy. If that matters, I recommend using the Storable module and its `dclone` function. This won't solve the problem of references to items outside the structure, but that's not usually a problem that needs solving anyway.	[reply] [d/l]
Re^2: Copy of an anonymous hash? by tphyahoo (Vicar) on Apr 26, 2005 at 14:16 UTC
I believe `my $new_element = \%{$hash_array[$index]};` [download] would also work. (Right?) UPDATE: I meant, my referencing syntax would work as well as hollis. This is right... right?	[reply] [d/l]
Re^3: Copy of an anonymous hash? by Fletch (Bishop) on Apr 26, 2005 at 15:04 UTC
Nope, it'll still point to the same underlying hash. `freebie:~ 702> perl -le '$a={qw(a b)};$b=\%{$a};print "$a\t$b"' HASH(0x804c844) HASH(0x804c844)` [download]	[reply] [d/l]