Re: Accessing keys through values

In case your values are unique in the hash, you can simply reverse it

%h  = (a=>"A", "b"=>"B");
%h2 = reverse %h;
print $h2{A}; #a
[download]

If not, you'll have to iterate over the hash.

%h  = (a=>"A", "b"=>"B", "bb" => "B");
for ( keys %h )
{
  print $_ if $h{$_} eq "B";
}
[download]

oh ... and please use code-tags.

holli, /regexed monk/

Comment on Re: Accessing keys through values Select or Download Code

Replies are listed 'Best First'.
Re^2: Accessing keys through values by cybersmithuk (Initiate) on Apr 26, 2005 at 10:52 UTC
As you have seen my script, the output I am getting is in the while loop and that too in the variable called $peak. Now, I should match which key contains the $peak value. For example, I have got the output from $peak as 41.876000 45.063000 48.922000 44.042000 46.863000 44.727000 45.491000 46.154000 I should search all the keys which hold these values and print both key and value like 78.3 =====> 41.876000. In this the 78.3 is the "key" and 41.876000 is the "value" (output from $peak in the while loop).	[reply]

Replies are listed 'Best First'.

Re^2: Accessing keys through values
by cybersmithuk (Initiate) on Apr 26, 2005 at 10:52 UTC

As you have seen my script, the output I am getting is in the while loop and that too in the variable called $peak. Now, I should match which key contains the $peak value. For example, I have got the output from $peak as 41.876000 45.063000 48.922000 44.042000 46.863000 44.727000 45.491000 46.154000 I should search all the keys which hold these values and print both key and value like 78.3 =====> 41.876000. In this the 78.3 is the "key" and 41.876000 is the "value" (output from $peak in the while loop).

[reply]