Re^4: .. operator and not including the condition of right operand

That will work except when $1 is 0 (which it can be). The three-dot form isn't making a difference in results here, although I suppose it saves some pattern matching. I'd do

        if((/^1/ ... /^0/) =~ /^\d+$/ ){
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although in this case

        if(/^1/ ... (/^0/ && next)){
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works rather neatly.

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