in reply to uninitialized value in split

What are you splitting $line on? The first argument to split is the delimiter to split on. The second argument is the scalar to split up. If it's unspecified, it defaults to $_, which is undefined in your examples. You probably want my @words = split ' ', $line; - try that out and see if it helps.

I want to commend you on using strict and warnings. Excellently done!

  • In general, if you think something isn't in Perl, try it out, because it usually is. :-)
  • "What is the sound of Perl? Is it not the sound of a wall that people have stopped banging their heads against?"

Replies are listed 'Best First'.
Re^2: uninitialized value in split
by jjohhn (Scribe) on May 17, 2005 at 03:07 UTC
    I thought that after a shift in a subroutine, $_ contains the value of the shift.
    But I did what you said, and now have a different problem which I will look at for awhile.
[reply]
      According to perldoc -f shift 
          shift ARRAY
    shift   Shifts the first value of the array off and returns it,
            shortening the array by 1 and moving everything down. If t
+here
            are no elements in the array, returns the undefined value.
+ If
            ARRAY is omitted, shifts the @_ array within the lexical s
+cope
            of subroutines and formats, and the @ARGV array at file sc
+opes
            or within the lexical scopes established by the "eval ''",
            "BEGIN {}", "INIT {}", "CHECK {}", and "END {}" constructs
+.

            See also "unshift", "push", and "pop". "shift" and "unshif
+t" do
            the same thing to the left end of an array that "pop" and 
+"push"
            do to the right end.

      [download]

      No mention of setting $_

      TheStudent
[reply]
[d/l]
        I guess I confused shifting the value from @_ with setting the value of $_. Thanks.
[reply]

In Section Seekers of Perl Wisdom