Re: dynamic filenames, indirect filehandles

in reply to dynamic filenames, indirect filehandles

IMHO, I'm not sure what you're trying to achieve here, but here are a few pointers:

Always use strict;
Why confuse yourself with the ARGuments? Why not use $ARGV[0], $ARGV[1]..etc?
open FH, '<', '<path of file>';
Why are you appending a file handle ($outfile)with $sl ?
Indent

Update:Use split;

Cheers,
Rupesh.

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Re^2: dynamic filenames, indirect filehandles by jjohhn (Scribe) on May 19, 2005 at 04:19 UTC
Thanks rupesh I don't mean to append the filehandle, I mean to append the name ("path") of the file. Incrementing the name is just what I want to achieve. This is the core of my question: For a 20,000 line $readfile, I want to produce 20 separate $outfiles, files, named (for example) "outa", "outb", etc.	[reply]
Re^2: dynamic filenames, indirect filehandles by TheStudent (Scribe) on May 19, 2005 at 04:33 UTC
Why are you appending a file handle ($outfile)with $sl ? So that he can say $outfile++ and generate unique file names for each split file. Lou	[reply]

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