in reply to Testing if Two Arrays are Ordered in a Same Way
sub test_ordered { my ( $ref, $test ) = @_; # $i scans the indices of @$ref; # $matched keeps count of # of elements matched in @$test; my ( $i, $matched ) = ( 0, 0 ); OUTER: for ( @$test ) { while ( $i < @$ref or return 0 ) { if ( $ref->[ $i++ ] eq $_ ) { last OUTER if ++$matched == @$test; last; } } } return 1; }
Updates: Minor tweaks. Fixed behavior for the empty @$test case (returns 1).
the lowliest monk
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