Re: How do I read all the file names of a directory into an array?

I would like to read the names of all the files in a directory of mine into an array so that I can convert each file name into a link to that file.

very simply, use opendir, readdir, and closedir


my $dir = '/';               ## rem trailing slash
my $body;                    ## our file list
my $saveFile = '/dev/null';  ## file to save links

opendir( MYDIR, $dir ) or die 'opendir';
$body =
   join( "\n",                           ## make it legible
      map  { '<a href="$_">$_</a><br>' } ## format each file
      sort { $a cmp $b }                 ## sort them
      grep { ! /^\./ }                   ## no .name files
      grep { -T "$dir$_ }                ## only text files
      readdir MYDIR
   );
closedir MYDIR;

## build your link page
## using $body
open( FILE, $saveFile ) or die 'open';
print FILE <<EOF;
<HTML>
<HEAD>
<TITLE>My Files</TITLE>
<BODY>
$body
</BODY>
</HTML>
EOF
close FILE;
[download]

see also join, grep, map, and sort
( along with Schwartzian Transform and file test operators )

--jj--

Comment on Re: How do I read all the file names of a directory into an array? Download Code

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Re: Answer: How do I read all the file names of a directory into an array? by chipmunk (Parson) on Dec 12, 2000 at 02:06 UTC
A tip about grep and map: using two in a row is almost always unnecessary. For example, the grep {} grep {} in the above code can be made into a single grep {} with the and operator. `map { qq{<a href="$_">$_</a><br>} } ## format each file sort ## sort them grep { !/^\./ and -T "$dir$_" } ## no .name files, text fil +es only readdir MYDIR` [download]	[reply] [d/l]