Variable Declaration in Perl6

goober99 has asked for the wisdom of the Perl Monks concerning the following question:

I have been playing around with Pugs ever since the project started. I have recently been looking over the examples and trying to write Perl6 scripts of my own. I've run into one frustration so far. When I assign a value to a variable like this:

$learning = 'perl6';

I get the following error message from Pugs:

*** Undeclared variable: "$learning"

Now if I change my code to:

my $learning = 'perl6';

it works fine. Are you not going to be able to simply declare variables by creating them as you were in Perl5? I now a lot of people recommend always using my anyway, but I really like the option of either way. Is there anyway to turn off the option in Pugs that causes an error with the first example?

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Re: Variable Declaration in Perl6 by mrborisguy (Hermit) on Jun 01, 2005 at 22:04 UTC
I think it has to do with the start of your file. If you say 'use v6;' - which I don't think is necessary in pugs right now - that defaults to strict. However, if you say 'v6' without the 'use', then that isn't strict, so you would be able to do what you want to do. I believe those are the rules in the perl6 language. However, as far as I know, pugs is just automatically in strict mode, no matter what you do. -Bryan	[reply]
Re: Variable Declaration in Perl6 by duff (Parson) on Jun 02, 2005 at 05:28 UTC
Read throught this for more background and for a way around the strictness. Though I'm not sure the pugs implements it yet. duff	[reply]
Re: Variable Declaration in Perl6 by eric256 (Parson) on Jun 01, 2005 at 23:55 UTC
I'm kinda curious why you wouldn't want it to require my. My definitly stops bugs, but what is the benefit of not needing it? `my $learning = 'perl6'; say $laerning; # error with strict, silent bug without` [download] ___________ Eric Hodges	[reply] [d/l]